# How do you find the slope of (6, 8) & (10, -5) ?

The slope of the line through $\left(6 , 8\right)$ and $\left(10 , - 5\right)$ is
$\left(- \frac{13}{4}\right)$
Slope = $\frac{\Delta y}{\Delta x} = \frac{8 - \left(- 5\right)}{6 - 10} = - \frac{13}{4}$