Question

How do you find the slope of a line perpendicular to the line to the line through the points (7,-10) and (6,-1)?

Answer 1

The perpendicular slope would be `m=1/9`

Explanation:

Let's begin by finding the slope of the line through the two points, `(7,-10)` and `(6,-1)`

Slope is The change in `y` rise over the change in `x` run.

`m = (Deltay)/(Deltax)`

and can be found using the equation

`m=(y_2-y_1)/(x_2-x_1)`

For the points given the coordinates are

`x_1 = 7`
`y_1 = -10`
`x_2 = 6`
`y_2=-1`

Plug in the values and solve for slope

`m=(-1 -(-10))/(6-7)`

`m = 9/-1`

`m =-9`

The line perpendicular to this line would have a slope that is the inverse of this line. Both in sign and reciprocal.

#m - 1/9