How do you find the slope of the line #3x-2y=-8#?

Question

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Answer 1 · 2015-04-04T20:39:16

Answer: #3/2#

Solution

Arrange this in the form:

#y = mx + c #

where #m # is the gradient of the line and #c# is the y intercept

It goes...
#3x - 2y = -8#

#=> 2y = 3x + 8#

#=> y = 3/2x + 4#

Hence #m = 3/2#

ALTERNATIVELY you would differentiate the equation implicitly:

You have #3x - 2y = -8#. Differentiate each term you get,

#3 -2(dy)/(dx) = 0#

# => (dy)/(dx) = 3/2 #

#(dy)/(dx) # is the gradient of the line