How do you find the slope of the line passing through the points (-2,5), (6,-3)?

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Answer 1 · 2018-04-04T04:40:56

The slope is #-1#.
Here's how I did it:

To find the slope of something, we do #(triangley)/(trianglex)#, or change in y over change in x, or #(y_2-y_1)/(x_2-x_1)#.

In your question, you have two points on the line, #(-2, 5)# and #(6, -3)#. So we can plug them into the equation above and solve for the slope.

(below, m means slope)
#m = (-3-5)/(6-(-2))#

#m = (-8)/8#

#m = -1#

The slope is #-1#.

Hope this helps!