Question

How do you find the slope that is perpendicular to the line `3x+10y=-20`?

Answer 1

`=10/3`

Explanation:

`y=mx+c` Where `m` is the slope
Hence the slope of the line Perpendicular to the line is `=-1/m`
In the equation `3x+10y=-20`
or
`10y=-3x-20`
or
`y=-3x/10-20/10`
or
`y=-3x/10-2`
Slope `=-3/10`
Hence the slope of the line Perpendicular to the line is `=10/3`