# How do you find the slope that is perpendicular to the line  3x+10y=-20?

Aug 7, 2016

$= \frac{10}{3}$

#### Explanation:

$y = m x + c$ Where $m$ is the slope
Hence the slope of the line Perpendicular to the line is $= - \frac{1}{m}$
In the equation $3 x + 10 y = - 20$
or
$10 y = - 3 x - 20$
or
$y = - 3 \frac{x}{10} - \frac{20}{10}$
or
$y = - 3 \frac{x}{10} - 2$
Slope $= - \frac{3}{10}$
Hence the slope of the line Perpendicular to the line is $= \frac{10}{3}$