How do you find the slope that is perpendicular to the line (4, 19) and (-3, 5)?

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Answer 1 · 2018-03-18T05:19:58

The slope of the line which is perpendicular to the line #(4, 19); (-3, 5)# is #-1/2#

Given -

#(4, 19); (-3, 5)#

The slope of the given line

#x_1=4#
#y_1=19#
#x_2=-3#
#y_2=5#

#m_1=(y_2-y_1)/(x_2-x_1)=(5-19)/(-3-4)=(-14)/(-7)=2#

The slope of the line which is perpendicular to a given line

#m_2=(-1)/m_1=(-1)/2=-1/2#

The slope of the line which is perpendicular to the line #(4, 19); (-3, 5)# is #-1/2#