How do you find the slope that is perpendicular to the line #-9x = -6y + 18#?
1 Answer
Jul 4, 2017
Explanation:
#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#
#m_(color(red)"perpendicular") = -1/m#
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b the y-intercept.
#"to obtain the slope of the given line"#
#"rearrange " -9x=-6y+18" into slope-intercept form"#
#rArr-6y=-9x-18#
#"divide All terms by - 6"#
#(cancel(-6) y)/cancel(-6)=(-9)/(-6)x-18/(-6)#
#rArry=3/2x+3larrcolor(red)" in slope-intercept form"#
#rArrm=3/2#
#rArrm_(color(red)"perpendicular")=-1/(3/2)=-2/3#
