How do you find the slope that is perpendicular to the line #-9x = -6y + 18#?

1 Answer
Jul 4, 2017

Answer:

#"slope "=-2/3#

Explanation:

#"given a line with slope m then the slope of a line"#
#"perpendicular to it is"#

#m_(color(red)"perpendicular") = -1/m#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b the y-intercept.

#"to obtain the slope of the given line"#

#"rearrange " -9x=-6y+18" into slope-intercept form"#

#rArr-6y=-9x-18#

#"divide All terms by - 6"#

#(cancel(-6) y)/cancel(-6)=(-9)/(-6)x-18/(-6)#

#rArry=3/2x+3larrcolor(red)" in slope-intercept form"#

#rArrm=3/2#

#rArrm_(color(red)"perpendicular")=-1/(3/2)=-2/3#