# How do you find the slope that is perpendicular to the line  y = 6x + 2?

Dec 24, 2016

The slope of a perpendicular line will be $- \frac{1}{\textcolor{red}{6}}$

#### Explanation:

Let the slope of a line be called $\textcolor{red}{m}$

The slope of a line perpendicular to this first line will be $- \frac{1}{m}$

The line in this problem is in the slope intercept form:

$y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept.

Therefore, a line perpendicular to the line $y = \textcolor{red}{6} x + \textcolor{b l u e}{2}$
will have a slope of:

$- \frac{1}{\textcolor{red}{6}}$