How do you find the solution of the system of equations 6x - 3y - 4 = 06x3y4=0 and x + 2y - 4 = 0x+2y4=0?

1 Answer
May 7, 2015

Rewrite the given equations as:
6x-3y=46x3y=4
x+2y = 4x+2y=4

{: ("[1] ",6x,-3y," =", 4) ,("[2] ",x,+2y,"=",4) ,("[3]=[2]"xx6" ",6x,+12y,"=",24) ,("[4]=[3]-[1] ",,+15y,"=",20) ,("[5]=[4]/15 ",,y,"=",4/3) ,("[6]=[1]with[5]",6x,-4,"=",4) ,("[7]",6x,,"=",8) ,("[8]",x,,"=",4/3) :}

(x,y) = (4/3,4/3)