# How do you find the solution of the system of equations x-2y=3 and x-y=3?

May 4, 2015

$\text{[1] } x - 2 y = 3$
$\text{[2] } x - y = 3$

$\text{[3] = [1] - [2] } - y = 0$
Substituting back into $\text{ [2]}$
$x - 0 = 3$
$x = 3$

Solution for the given system of equations is
$\left(x , y\right) = \left(3 , 0\right)$