How do you find the solution of the system of equations $x+y=6$ and $x-y=2$ ?

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Answer 1 · 2015-05-19T15:00:53

Let's isolate one variable in one equation and take the value we find and substitute it in the other equation, as follows.

Let's isolate $x$ in the first, for example:

$x=6-y$

Nos, substituting it in the second:

$(6-y)-y=2$
$6-2y=2$
$-2y=-4$
$y=1/2$

If $y=1/2$ and $x=6-y$ , then

$x=6-1/2$
$x=11/2$

How do you find the solution of the system of equations x+y=6 x+y=6 and x-y=2x-y=2?