How do you find the solution set for 5x² - 30x = -25 ? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Pratik B. May 24, 2015 #5x^2-30x+25=0# #5(x^2-6x+5)=0# # => x^2-6x+5=0# #x^2-5x-x+5=0# #x(x-5)-1(x-5)=0# #=>(x-5)(x-1)=0# #x=5,1# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2685 views around the world You can reuse this answer Creative Commons License