How do you find the solution to the quadratic equation # 0 = x^2 + 5x + 6#?

3 Answers
Jun 20, 2018

Answer:

x=-2 or -3

Explanation:

#x^2+5x+6=0#

#x^2+2x+3x+6=0#

#x*(x+2)+3(x+2)=0#

#(x+2)*(x+3)=0#

#x=-2 or -3#

Jun 20, 2018

Answer:

#x=-3, x=-2#

Explanation:

Lets factorise:

#(x+3)(x+2)=0#

Check this is correct...

#x^2+3x+2x+6#

#rArr x^2+5x+6=0#

Now solve:

#(x+3)=0#

#therefore# #x=-3#

#(x+2)=0#

#therefore# #x=-2#

Jun 21, 2018

Answer:

#x=-2# and #x=-3#

Explanation:

Are there any two numbers that sum to the middle term (#5#), and have a product of the last term (#6#)?

After some trial and error, we arrive at

#2# and #3#. Thus, we can factor the right side of our quadratic as

#0=(x+2)(x+3)#

Setting both of our factors equal to zero, we get

#x=-2# and #x=-3#

Hope this helps!