Question

How do you find the solution to the quadratic equation `2x^2-5=0`?

Answer 1

Starting with `2x^2 - 5 = 0`, first add 5 to both sides to get:

`2x^2 = 5`

Divide both sides by 2 to get:

`x^2 = 5/2`

Take the square root of both sides (allowing both positive and negative roots) to get:

`x = +-sqrt(5/2) = +-sqrt(5)/sqrt(2)`