# How do you find the solution to the quadratic equation 2x^2-5=0?

May 12, 2015

Starting with $2 {x}^{2} - 5 = 0$, first add 5 to both sides to get:

$2 {x}^{2} = 5$

Divide both sides by 2 to get:

${x}^{2} = \frac{5}{2}$

Take the square root of both sides (allowing both positive and negative roots) to get:

$x = \pm \sqrt{\frac{5}{2}} = \pm \frac{\sqrt{5}}{\sqrt{2}}$