How do you find the solution to the quadratic equation #36=5x+x^2#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer bp May 9, 2015 x= -9,4 Factorise the quadratic #x^2+5x-36=0# by splitting the middle term #x^2 +9x-4x-36#=0. The factors would be (x+9)(x-4)=0. The solution would be x= -9, 4 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2046 views around the world You can reuse this answer Creative Commons License