Question

How do you find the solution to the quadratic equation `4x^2-13x+3=0`?

Answer 1

`4x^2-13x+3 = 0`

The left side has a fairly simple factoring
`(4x-1)(x-3) = 0`

So either `4x-1 = 0 rarr x=1/4`
or
`x-3=0 rarr x=3`