# How do you find the solution to the quadratic equation 4x^2-13x+3=0?

$4 {x}^{2} - 13 x + 3 = 0$
$\left(4 x - 1\right) \left(x - 3\right) = 0$
So either $4 x - 1 = 0 \rightarrow x = \frac{1}{4}$
$x - 3 = 0 \rightarrow x = 3$