Question

How do you find the solution to the quadratic equation `x^2-2x-8=0`?

Answer 1

`y = x^2 - 2x - 8 = 0`
Compose factor pairs of (-8)-->(-1, 8)(-2, 4). This sum is (4 - 2 = 2 = -b)
Then, the 2 real roots are: -2 and 4.
There is no need for factoring or using the formula.