# How do you find the solution to the quadratic equation x^2+ x - 42 = 0?

${x}^{2} + x - 42 = 0$
$\left(x + 7\right) \left(x - 6\right) = 0$
So either $\left(x + 7\right) = 0$ or $\left(x - 6\right) = 0$
$x = - 7$ or $x = + 6$