# How do you find the standard form of #4y^2-8y-x+1=0#?

##### 1 Answer

Feb 8, 2016

but since this was asked under "Geometry of an Ellipse" the question was probably meant to be

#### Explanation:

A general polynomial is said to be in "standard form" if every term has a degree greater than or equal to all terms that follow it.

#{:(4y^2,"degree "2),(-8y,"degree "1),(-x,"degree "1),(+1,"degree "0):}rArr "in standard form"#

However certain "special polynomials" such as those representing ellipse or hyperbola have their own "standard forms".

If the given equation was meant to have