# How do you find the standard form of the following equation Y=(x+3)^2+1?

Nov 11, 2016

Standard form is $y = {x}^{2} + 6 x + 10$

#### Explanation:

$y = {\left(x + 3\right)}^{2} + 1$

Multiply, or FOIL, the term being squared in the parentheses:
$y = \left(x + 3\right) \left(x + 3\right) + 1$
$y = {x}^{2} + 3 x + 3 x + 9 + 1$

Combine like terms:
$y = {x}^{2} + 6 x + 10$