# How do you find the sum of #Sigma 2i^2# where i is [0,5]?

##### 1 Answer

Nov 10, 2017

#### Answer:

# sum_(i=0)^5 2i^2 = 110 #

#### Explanation:

We seek:

# sum_(i=0)^5 2i^2 = 2 .0^2 + 2 .1^2 + 2 .2^2 + 2 .3^2 + 2 .4^2 + 2 .5^2 #

# \ \ \ \ \ \ \ \ \ \ \ = 2 (0^2 + 1^2 + 2^2 + 3^2 + 4^2 + 5^2 ) #

# \ \ \ \ \ \ \ \ \ \ \ = 2 (0 + 1 + 4+ 9 + 16 + 25 ) #

# \ \ \ \ \ \ \ \ \ \ \ = 2 (55 ) #

# \ \ \ \ \ \ \ \ \ \ \ = 110 #