How do you find the sum of the first 32 terms of the series #34+31+28+25+22...#?

1 Answer
Jan 9, 2017

The sum of the first #32# terms of the series is #-400#

Explanation:

As the terms in the series #34+31+28+25+22......# are constantly coming down starting from first term #34# by #3#,

this is an arithmetic series staring from #a=34# and #d=-3#

The sum of such a series up to #n# terms is

#n/2(2a+(n-1)d)#

Hence, the sum of the first #32# terms of the series is

#32/2xx(2xx34+(32-1)xx(-3))#

= #16xx(68-31xx3)#

= #16xx(68-93)#

= #16xx(-25)#

= #-400#