# How do you find the sum of the geometric series 8+4+2+1+…?

The sum of a convergent geometric series ${\sum}_{n = 0}^{\infty} a {r}^{n}$ is $\frac{a}{1 - r}$. Since $a = 8$ and $r = \frac{1}{2}$ in the posted geometric series, the sum is $\frac{8}{1 - \frac{1}{2}} = 16$.