Geometric Series
Key Questions
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You can find the common ratio
#r# by finding the ratio between any two consecutive terms.#r=a_1/a_0=a_2/a_1=a_3/a_2=cdots=a_{n+1}/a_n=cdots# For the geometric series
#sum_{n=0}^infty(-1)^n{2^{2n}}/5^n# , the common ratio#r=a_1/a_0={-2^2/5}/{1}=-4/5# -
The sum of a convergent geometric series
#sum_{n=0}^{infty}ar^n# is#frac{a}{1-r}# . Since#a=8# and#r=1/2# in the posted geometric series, the sum is#frac{8}{1-frac{1}{2}}=16# . -
It's the sum of a sequence of terms where each term equals the previous one multiplied by a given ratio (e.g.
#1 + 2 + 4 + 8...# ).
Questions
Tests of Convergence / Divergence
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Geometric Series
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Nth Term Test for Divergence of an Infinite Series
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Direct Comparison Test for Convergence of an Infinite Series
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Ratio Test for Convergence of an Infinite Series
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Integral Test for Convergence of an Infinite Series
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Limit Comparison Test for Convergence of an Infinite Series
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Alternating Series Test (Leibniz's Theorem) for Convergence of an Infinite Series
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Infinite Sequences
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Root Test for for Convergence of an Infinite Series
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Infinite Series
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Strategies to Test an Infinite Series for Convergence
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Harmonic Series
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Indeterminate Forms and de L'hospital's Rule
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Partial Sums of Infinite Series