Question

How do you find the sum of the infinite geometric series a1 = 42 and r = 6/5?

Answer 1

It diverges and has no real sum since `|r|>1`

Explanation:

Since `\|r|=6/5>1`, it implies that the series does not converge and hence it diverges to infinity and has no real sum.
That is `sum_(n=1)^oo42*(6/5)^(n-1)=oo !in RR`