Question

How do you find the sum of the infinite geometric series given `Sigma3(0.5)^(n-1)` from n=1 to `oo`?

Answer 1

`6`

Explanation:

This is an infinite geometric series with `a = 3` and `r = 0.5`.

`s_oo = a/(1 -r)`

`s_oo = 3/(1 - 0.5)`

`s_oo = 3/0.5`

`s_oo = 6`

Hopefully this helps!