# How do you find the sum of the infinite geometric series given Sigma3(0.5)^(n-1) from n=1 to oo?

Jan 5, 2017

$6$

#### Explanation:

This is an infinite geometric series with $a = 3$ and $r = 0.5$.

${s}_{\infty} = \frac{a}{1 - r}$

${s}_{\infty} = \frac{3}{1 - 0.5}$

${s}_{\infty} = \frac{3}{0.5}$

${s}_{\infty} = 6$

Hopefully this helps!