# How do you find the sum of the series i/(i-1) from i=2 to 6?

Nov 22, 2016

${\sum}_{i = 2}^{6} \frac{i}{i - 1} = \frac{437}{60}$
${\sum}_{i = 2}^{6} \frac{i}{i - 1} = \frac{2}{2 - 1} + \frac{3}{3 - 1} + \frac{4}{4 - 1} + \frac{5}{5 - 1} + \frac{6}{6 - 1}$
$\therefore {\sum}_{i = 2}^{6} \frac{i}{i - 1} = \frac{2}{1} + \frac{3}{2} + \frac{4}{3} + \frac{5}{4} + \frac{6}{5}$
$\therefore {\sum}_{i = 2}^{6} \frac{i}{i - 1} = \frac{437}{60}$