# How do you find the sum or difference of (2ab-3a+4b)+(5a+4ab)?

Jul 3, 2017

See a solution process below:

#### Explanation:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$2 a b - 3 a + 4 b + 5 a + 4 a b$

Next, group like terms:

$- 3 a + 5 a + 2 a b + 4 a b + 4 b$

Now, combine like terms:

$\left(- 3 + 5\right) a + \left(2 + 4\right) a b + 4 b$

$2 a + 6 a b + 4 b$

If necessary, you can factor a $2$ out of each term giving:

$\left(2 \cdot a\right) + \left(2 \cdot 3 a b\right) + \left(2 \cdot 2 b\right)$

$2 \left(a + 3 a b + 2 b\right)$