How do you find the sum or difference of #(2ab-3a+4b)+(5a+4ab)#?

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Answer 1 · 2017-07-03T15:17:40

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#2ab - 3a + 4b + 5a + 4ab#

Next, group like terms:

#-3a + 5a + 2ab + 4ab + 4b#

Now, combine like terms:

#(-3 + 5)a + (2 + 4)ab + 4b#

#2a + 6ab + 4b#

If necessary, you can factor a #2# out of each term giving:

#(2 * a) + (2 * 3ab) + (2 * 2b)#

#2(a + 3ab + 2b)#