# How do you find the sum or difference of (2c^2+6c+4)+(5c^2-7)?

May 24, 2017

$7 {c}^{2} + 6 c - 7$

See the explanation for the process.

#### Explanation:

The parentheses are unnecessary because the two expressions are being added, so you are finding the sum of the terms.

$2 {c}^{2} + 6 c + 4 + 5 {c}^{2} - 7$

Group like terms.

$\left(2 {c}^{2} + 5 {c}^{2}\right) + \left(6 c\right) - \left(7\right)$

Combine like terms.

$7 {c}^{2} + 6 c - 7$