How do you find the sum or difference of $(2 x - 2 y + 1) - (3 y + 4 x)$ $(2x-2y+1)-(3y+4x)$ ?

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Answer 1 · 2016-11-07T18:45:14

$- 2 x - 5 y + 1$ $-2x - 5y + 1$

Step 1) Expand the terms in parenthesis remember to use the correct sign across the entire term in the parenthesis:

$2 x - 2 y + 1 - 3 y - 4 x$ $2x - 2y + 1 - 3y - 4x$

Step 2) Group like terms and simplify:

$(2 x - 4 x) - (2 y + 3 y) + 1$ $(2x - 4x) - (2y + 3y) + 1$

$(2 - 4) x - (2 + 3) y + 1$ $(2-4)x - (2+3)y + 1$

$- 2 x - 5 y + 1$ $-2x - 5y + 1$

How do you find the sum or difference of (2x−2y+1)−(3y+4x)(2x-2y+1)-(3y+4x)?