How do you find the sum or difference of #(2x+3x^2)-(7-8x^2)#?

1 Answer
Jul 23, 2017

#11x^2+2x-7#

Explanation:

#(2x+3x^2)-(7-8x^2)#

#(2x+3x^2)+[-1\cdot(7-8x^2)]#
#(2x+3x^2)+[-1(7)+(-1)(-8x^2)]# apply distributive property to second half
#(2x+3x^2)+[-7+8x^2]# simplify
#2x+3x^2-7+8x^2# remove parentheses and change signs where needed
#2x+11x^2-7# add like terms
#11x^2+2x-7# reorder to quadratic format