How do you find the sum or difference of #(3n^3+3n-10)-(4n^2-5n)+(4n^3-3n^2-9n+4)#?

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Answer 1 · 2017-02-10T13:37:58

See the entire solution process below:

First, remove all the terms from parenthesis being careful to manage the signs of each individual term correctly:

#3n^3 + 3n - 10 - 4n^2 + 5n + 4n^3 - 3n^2 - 9n + 4#

Next rewrite the expression grouping like terms together:

#3n^3 + 4n^3 - 4n^2 - 3n^2 + 3n + 5n - 9n - 10 + 4#

Now, combine like terms to complete the addition and sutraction:

#(3 + 4)n^3 + (-4 - 3)n^2 + (3 + 5 - 9)n - 6#

#7n^3 - 7n^2 - 1n - 6#

#7n^3 - 7n^2 - n - 6#