# How do you find the sum or difference of (3n^3+3n-10)-(4n^2-5n)+(4n^3-3n^2-9n+4)?

##### 1 Answer
Feb 10, 2017

See the entire solution process below:

#### Explanation:

First, remove all the terms from parenthesis being careful to manage the signs of each individual term correctly:

$3 {n}^{3} + 3 n - 10 - 4 {n}^{2} + 5 n + 4 {n}^{3} - 3 {n}^{2} - 9 n + 4$

Next rewrite the expression grouping like terms together:

$3 {n}^{3} + 4 {n}^{3} - 4 {n}^{2} - 3 {n}^{2} + 3 n + 5 n - 9 n - 10 + 4$

Now, combine like terms to complete the addition and sutraction:

$\left(3 + 4\right) {n}^{3} + \left(- 4 - 3\right) {n}^{2} + \left(3 + 5 - 9\right) n - 6$

$7 {n}^{3} - 7 {n}^{2} - 1 n - 6$

$7 {n}^{3} - 7 {n}^{2} - n - 6$