How do you find the sum or difference of #(3n^3-5n+n^2)-(-8n^2+3n^3)#?

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Answer 1 · 2017-03-31T12:02:42

See the entire solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#3n^3 - 5n + n^2 + 8n^2 - 3n^3#

Next, group like terms:

#3n^3 - 3n^3 + n^2 + 8n^2 - 5n#

Now, combine like terms:

#3n^3 - 3n^3 + 1n^2 + 8n^2 - 5n#

#(3 - 3)n^3 + (1 + 8)n^2 - 5n#

#0n^3 + 9n^2 - 5n#

#9n^2 - 5n#

Answer 2 · 2017-03-31T12:33:02

#n(9n-5)#

#(3n^3-5n+n^2)-(8n^2+3n^3)#

#:.=3n^3-5n+n^2+8n^2-3n^3#

#:.=9n^2-5n#

#:.=n(9n-5)#