How do you find the sum or difference of #(3z^2+2z-1)+(z^2-6)#?

1 Answer
May 8, 2017

See a solution process below:

Explanation:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#3z^2 + 2z - 1 + z^2 - 6#

Next, group like terms:

#3z^2 + z^2 + 2z - 1 - 6#

Now, combine like terms:

#3z^2 + 1z^2 + 2z - 1 - 6#

#(3 + 1)z^2 + 2z + (-1 - 6)#

#4z^2 + 2z + (-7)#

#4z^2 + 2z - 7#