# How do you find the sum or difference of (5a^2-4)+(a^2-2a+12)+(4a^2-6a+8)?

Mar 16, 2017

See the entire solution process below:

#### Explanation:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$5 {a}^{2} - 4 + {a}^{2} - 2 a + 12 + 4 {a}^{2} - 6 a + 8$

Next, group like terms:

$5 {a}^{2} + {a}^{2} + 4 {a}^{2} - 2 a - 6 a - 4 + 12 + 8$

Now, combine like terms:

$5 {a}^{2} + 1 {a}^{2} + 4 {a}^{2} - 2 a - 6 a - 4 + 12 + 8$

$\left(5 + 1 + 4\right) {a}^{2} + \left(- 2 - 6\right) a + \left(- 4 + 12 + 8\right)$

$10 {a}^{2} - 8 a + 16$