# How do you find the sum or difference of (-8xy+3x^2-5y)+(4x^2-2y+6xy)?

Feb 27, 2017

See the entire solution process below:

#### Explanation:

First, remove all of the terms from parenthesis. Be careful to handle the signs of the individual terms correctly:

$\left(- 8 x y + 3 {x}^{2} - 5 y\right) + \left(4 {x}^{2} - 2 y + 6 x y\right)$ becomes:

$- 8 x y + 3 {x}^{2} - 5 y + 4 {x}^{2} - 2 y + 6 x y$

Next, group like terms:

$3 {x}^{2} + 4 {x}^{2} + 6 x y - 8 x y - 5 y - 2 y$

Now, combine like terms:

$\left(3 + 4\right) {x}^{2} + \left(6 - 8\right) x y + \left(- 5 - 2\right) y$

$7 {x}^{2} - 2 x y - 7 y$