How do you find the sum or difference of #(y+5)+(2y+4y^2-2)#?

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Answer 1 · 2017-05-08T22:56:17

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#y + 5 + 2y + 4y^2 - 2#

Next, group like terms:

#4y^2 + 2y + y + 5 - 2#

Now, combine like terms:

#4y^2 + 2y + 1y + 5 - 2#

#4y^2 + (2 + 1)y + (5 - 2)#

#4y^2 + 3y + 3#