How do you find the sum or difference of #(z^2+z)+(z^2-11)#?

1 Answer

#2z^2+z-11#

Explanation:

#(z^2+z)+(z^2-11)#

The hang up here appears to be what to do with the brackets. It can be thought of that each bracket has a #+1# that is being distributed through each of them, and so that will look like:

#color(red)(1)(z^2+z)+color(red)(1)(z^2-11))#

#color(red)(1)(z^2)+color(red)(1)(z)+color(red)(1)(z^2)-color(red)(1)(11)#

#z^2+z+z^2-11#

And we can now combine like terms:

#2z^2+z-11#