Question

How do you find the the axis of symmetry of the quadratic function `y=3x^2+6x+4`?

Answer 1

x = - 1

Explanation:

`y = 3x^2 + 6x + 4`
x-coordinate of the vertex, and the axis of symmetry:
`x = - b/(2a) = -6/6 = - 1`