How do you find the value of #(12(52div2^2))/6-2/3#?

1 Answer
Nov 18, 2016

Answer:

#76/3#

Explanation:

we have #(12(52-:2^2))/6 -2/3#

start with the operation between parentheses : #52-:2^2=52-:4 = 13#

we get #(12xx13)/6-2/3#

we simplify : #(6xx2xx13)/6 -2/3 = (2xx13)/1-2/3=26/1-2/3#

now it's easy : #(26xx3)/3-2/3=78/3-2/3=76/3#