How do you find the value of "a" such that #t^2 + 8t +a# is a perfect square?
You can use the algebraic identity
If you compared these two expressions, you'll notice that
Since, in your case,
Your expression will become
We can apply the identity
The middle term
So we can write the middle term of '
It tells us that the first term is 't' and the second one is '4'