How do you find the value of #cot 0#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer VNVDVI Apr 21, 2018 #cot0# doesn't exist; the cotangent doesn't exist for values of #x=npi.# Explanation: Recall that #cotx=cosx/sinx.# Then, #cot0=cos0/sin0#. #cos0=1, sin0=0,# so #cot0=1/0# doesn't exist (division by zero). This gives rise to the fact that #cotx# doesn't exist for #x=npi.# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 19229 views around the world You can reuse this answer Creative Commons License