How do you find the value of cot 0? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer VNVDVI Apr 21, 2018 cot0 doesn't exist; the cotangent doesn't exist for values of x=npi. Explanation: Recall that cotx=cosx/sinx. Then, cot0=cos0/sin0. cos0=1, sin0=0, so cot0=1/0 doesn't exist (division by zero). This gives rise to the fact that cotx doesn't exist for x=npi. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 19658 views around the world You can reuse this answer Creative Commons License