How do you find the value of #csc (sin (2/3))#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Jun 11, 2015 Find the value of csc (arcsin (2/3)) Explanation: #sin x = 2/3# --> x ? #sin x = 2/3 = 0.67 # --> #x = 41.81# and x = 180 - 41.81 =# 138.19# a. #csc (41.81) = 1/sin (41.81) # = #1/0.67 = 1.49# (Quadrant I) b. #csc (138.19) = csc (-41.81) = 1/sin (-41.81)# = #= 1/-0.67# = -1.49 (Quadrant II) Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2879 views around the world You can reuse this answer Creative Commons License