Question

How do you find the value of k so that the remainder is zero given `(x^3+18x^2+kx+4)div(x+2)`?

Answer 1

Solution: `k=34`

Explanation:

`x^3 +18 x^2 +k x +4 -: (x+2); x+2=0 or x =-2` .

The remainder will be zero if we put `x = -2` in the dividend.

`f(x)= x^3 +18 x^2 +k x +4`

`f(-2)= -8 +72 - 2 k +4 =0` or

`2 k= 68 or k =34`

Solution: `k=34` [Ans]