How do you find the value of #log_2 8# using the change of base formula?

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Answer 1 · 2016-11-13T02:25:53

The change of base formula states:

#color(green)(log_n(a) = loga/logn)#

So:

#log_2(8)#

#=> log8/log2#

Write in powers of #2#.

#=>(log2^3)/(log2^1)#

Use the rule #logn^a = alogn#.

#=>(3log2)/(1log2)#

#=> 3#

Hopefully this helps!