Question

How do you find the value of `sec^2(225^circ)`?

Answer 1

`1/4`

Explanation:

`sec^2(225 ^circ) = sec^2(2xx90 + 45)^circ`

`rArr [-sec45^circ]^2`

Note:- [`225^circ` is in 3rd Quadrant where only tan & cot positive.]

`rArr [-1/(sqrt 2)]^2`

`rArr 1/4`