How do you find the value of #sin (157 1/2)#? Trigonometry Trigonometric Identities and Equations Half-Angle Identities 1 Answer A. S. Adikesavan Jun 30, 2016 #sqrt((sqrt 2-1)/(2sqrt2))#=0.3827, nearly. Explanation: #167.5^o# is angle in the 2nd quadrant. So, sin is positive. #Also, sin 157.5^o=sin (180^0-157.5^o)=sin 22.5^o# Now, use #cos 2t = (1-2sin^2 t)# #cos 45^o=1/sqrt 2=(1-2 sin^2 22.5^o)# Solving for positive root, #sin 22.5^o=sqrt((1-1/sqrt 2)/2)# Answer link Related questions What is the Half-Angle Identities? How do you use the half angle identity to find cos 105? How do you use the half angle identity to find cos 15? How do you use the half angle identity to find sin 105? How do you use the half angle identity to find #tan (pi/8)#? How do you use half angle identities to solve equations? How do you solve #\sin^2 \theta = 2 \sin^2 \frac{\theta}{2} # over the interval #[0,2pi]#? How do you find the exact value for #sin105# using the half‐angle identity? How do you find the exact value for #cos165# using the half‐angle identity? How do you find the exact value of #cos15#using the half-angle identity? See all questions in Half-Angle Identities Impact of this question 6975 views around the world You can reuse this answer Creative Commons License