Question

How do you find the value of so that the remainder is zero of `x^2+kx-6 div (x+1)`?

Answer 1

`k=-5`

Explanation:

We need that

`(x^2+kx-6)/(x+1) = q(x)` with `q(x)` a polynomial.

Also equivalently

`x^2+kx-6 = q(x)(x+1)`

Now making `x = -1` we have

`1-k-6=0` then `k = -5`