How do you find the value of $tan45$ using the half angle identity?

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Answer 1 · 2016-07-20T14:35:36

Using $tan 90^o=+-oo$ , tan 45^o=1#

$tan 90^o=+-oo=(2 tan 45^o)/(1-tan^2 45^o$ .

Equating the denominator to 0,

$tan^2 45^o=1 and tan 45^o=+-1$

The first quadrant tangent $tan 45^o > 0$ .

So, $tan 45^o = 1$ ..

Note that tan x is discontinuous at x = $90^$ and that

limits $tan 90+-^o=+-oo$ .

How do you find the value of tan45tan45 using the half angle identity?