How do you find the value of the discriminant and determine the nature of the roots #x^2 – 64 = 0 #?

1 Answer
Apr 16, 2018

Answer:

#color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)#

Explanation:

https://newcollegeswindonmaths.wordpress.com/2016/04/10/core-1-discriminant/

#x^2 - 64 = 0#

It is in the form #ax^2 + bx + c = 0, " with "a = 1, b = 0, c = -64#

#"Discriminant " D = b^2 - 4 a c = 0 - (4 * 1 * -64) = 256#

Since #color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)#