# How do you find the value of the discriminant and determine the nature of the roots x^2 – 64 = 0 ?

Apr 16, 2018

color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)

#### Explanation:

${x}^{2} - 64 = 0$

It is in the form $a {x}^{2} + b x + c = 0 , \text{ with } a = 1 , b = 0 , c = - 64$

$\text{Discriminant } D = {b}^{2} - 4 a c = 0 - \left(4 \cdot 1 \cdot - 64\right) = 256$

Since color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)